4x^2+7x+12=10

Solution for 4x^2+7x+12=10 equation:

4x^2+7x+12=10

We move all terms to the left:

4x^2+7x+12-(10)=0

We add all the numbers together, and all the variables

4x^2+7x+2=0

a = 4; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·4·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{17}}{2*4}=\frac{-7-\sqrt{17}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{17}}{2*4}=\frac{-7+\sqrt{17}}{8}
$